Daniel, Bobby and Mark have some beads. The ratios of their beads are as follows:
Daniel : (Daniel + Bobby + Mark) = 3 : 7
Bobby : (Daniel + Mark) = 1 : 3
Mark has 4 beads more than Bobby. In the end, Mark gives away all he has to Bobby and Daniel so that both Bobby and Daniel end up with the same number of beads, how many beads has Daniel received from Mark?
Bobby |
Mark |
Daniel |
Total |
4x4 |
3x4 |
7x4 |
1x7 |
3x7 |
4x7 |
7 u |
9 u |
12 u |
28 u |
The total number of beads is repeated. Make the total number of beads the same. LCM of 7 and 4 is 28.
Number of beads that Mark has more than Bobby
= 9 u - 7 u
= 2 u
2 u = 4
1 u = 4 ÷ 2 = 2
|
Bobby |
Mark |
Daniel |
Before |
7 u |
9 u |
12 u |
Change |
+ 7 u |
- 9 u |
+ 2 u |
After |
14 u |
0 u |
14 u |
Number of beads that Daniel has received from Mark
= 14 u - 12 u
= 2 u
= 2 x 2
= 4
Answer(s): 4