There were some starfruits and passion fruits in Container D and Container E. In Container D, the ratio of the starfruits to the number of passion fruits was 4 : 1. In Container E, the ratio of the number of starfruits to the number of passion fruits was 3 : 2. There were 2 times as many fruits in Container D as in Container E. After another 40 passion fruits were put into Container E, the ratio of the number of starfruits to the number of passion fruits in Container E became 1 : 2. How many fruits were there in Container D?

Container D		Container E
2x5 = 10 u		1x5 = 5 u
Starfruits	Passion fruits	Starfruits	Passion fruits
4x2	1x2	3	2
8 u	2 u	3 u	2 u

The total number of fruits in Container D is repeated.  Make the total number of fruits in Container D the same.  LCM of 2 and 5 is 10.

The total number of fruits in Container E at first is repeated.  Make the total number of fruits in Container E the same.  LCM of 1 and 5 is 5.

	Container D		Container E
	Starfruits	Passion fruits	Starfruits	Passion fruits
Before	8 u	2 u	3 u	2 u
Change				+ 40
After	8 u	2 u	1x3 = 3 u	2x3 = 6 u

Number of starfruits in Container E remains unchanged.  Make the number of starfruits in Container E the same.  LCM of 3 and 1 is 3.

Number of passion fruits put into Container E
= 6 u - 2 u
= 4 u

4 u = 40

1 u = 40 ÷ 4 = 10

Number of fruits in Container D
= 8 u + 2 u
= 10 u
= 10 x 10
= 100

Answer(s): 100