A jar contained $5 and $10 notes with a total value of $585. 4 pieces of $10 were exchanged for $5 notes of similar value. In the end, the number of $5 notes was the same as the $10 notes. How many $10 notes were there at first?
| |
$5 |
$10 |
| Before |
1 u - 8 |
1 u + 4 |
| Change |
+ 8 |
- 4 |
| After |
1 u |
1 u |
Total value of $5 and $10 notes remains unchanged after the exchange of notes of similar value.
Total value of 4 pieces of $10-notes
= 4 x 10
= $40
Number of $5-notes that 4 pieces of $10-notes were exchanged for
= 40 ÷ 5
= 8
| In the end |
$5 |
$10 |
Total |
| Number |
1 u |
1 u |
2 u |
| Value |
5 |
10 |
|
| Total Value |
5 u |
10 u |
15 u |
Total value of $5 and $10 notes
= 5 u + 10 u
= 15 u
15 u = 585
1 u = 585 ÷ 15 = 39
Number of $10 notes at first
= 1 u + 4
= 39 + 4
= 43
Answer(s): 43
