20% of the people are performers for a concert and the rest are spectators. 60% of the spectators are children and there are 560 less adult spectators than child spectators. How many child spectators must join so that 74% of the people are child spectators?
|
Performers |
Spectators |
|
1x5 |
4x5 |
|
|
Adults |
Children |
|
|
2x4 |
3x4 |
Before |
5 u |
8 u |
12 u |
Change |
|
|
+ ? |
After |
13x1 = 13 u |
37x1 = 37 u |
20% =
20100 =
15 60% =
60100 =
35 74% =
74100 =
3750The total number of spectators at first is repeated. Make the total number of spectators the same. LCM of 4 and 5 is 20.
Number of less adult spectators than child spectators at first
= 12 u - 8 u
= 4 u
4 u = 560
1 u = 560 ÷ 4 = 140
If some child spectators join, the total number of adult spectators and performers remains unchanged.
Number of child spectators who must join so that 74% of the people are child spectators
= 37 u - 12 u
= 25 u
= 25 x 140
= 3500
Answer(s): 3500