Gabriel, Sam and Ken shared a sum of money. Gabriel and Sam received 90% of the total amount of money. Sam and Ken received 50% of the total amount of money. Given that Gabriel received $80 more than Ken, how much was the sum of money that was shared by Gabriel and Ken?
| Gabriel |
Sam |
Ken |
Total |
| 9x1 |
1x1 |
10x1 |
| 1x5 |
1x5 |
2x5 |
| 5 u |
4 u |
1 u |
10 u |
90% =
90100 =
910 50% =
50100 =
12 The total amount of money that Gabriel, Sam and Ken shared is repeated. Make the total amount of money the same. LCM of 10 and 2 is 10.
Amount that Gabriel received more than Ken
= 5 u - 1 u
= 4 u
4 u = 80
1 u = 80 ÷ 4 = 20
Amount that Gabriel and Ken shared
= 5 u + 1 u
= 6 u
= 6 x 20
= $120
Answer(s): $120
