At the bowling alley, there were 40% as many women as men and 30% more children than women. Given that there were 12 more children than women at the bowling alley, how many adults were there altogether?
Women |
Men |
Children |
2x5 |
5x5 |
|
10x1 |
|
13x1 |
10 u |
25 u |
13 u |
40% =
40100 =
25Women : Men = 2 : 5
100% + 30% = 130%
130% =
130100 =
1310 Women : Children = 10 : 13
The number of women is repeated. Make the number of women the same. LCM of 2 and 10 is 10.
Number of more children than women
= 13 u - 10 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of adults
= 10 u + 25 u
= 35 u
= 35 x 4
= 140
Answer(s): 140