Min has a bag containing some green and yellow stickers. If she adds in 15 green stickers, 25% of the stickers in the bag are yellow. If she adds in another 22 yellow stickers, 50% of the stickers in the bag are yellow. How many green stickers are in the bag?
|
Green stickers |
Yellow stickers |
Before |
3 u - 15 |
1 u |
Change 1 |
+ 15 |
|
After 1 |
3x1 = 3 u |
1x1 = 1 u |
Change 2 |
|
+ 22 |
After 2 |
1x3 = 3 u |
1x3 = 3 u |
25% =
25100 =
1450% =
50100 =
12The number of green stickers remains unchanged at the second change when she adds in another 22 yellow stickers. Make the number of green stickers the same at the second change. LCM of 3 and 1 is 3.
Number of yellow stickers added
= 3 u - 1 u
= 2 u
2 u = 22
1 u = 22 ÷ 2 = 11
Number of green stickers at first
= 3 u - 15
= 3 x 11 - 15
= 33 - 15
= 18
Answer(s): 18