A store owner has 60 less lemons than chikoos. After he sold 70% of the lemons and 20% of the chikoos, he is left with 27 less lemons than chikoos. What fraction of the fruits left were lemons?
| |
Lemons |
Chikoos |
Comparing lemons
and chikoos at first |
|
60 less |
| Before |
10x1 =
10 u |
+ 60 |
5x2 =
10 u |
| Change |
- 7x1 =
- 7 u |
- 42 |
- 1x2 =
- 2 u |
| After |
3x1 =
3 u |
+ 18 |
4x2 =
8 u |
Comparing lemons
and chikoos in the end |
27 less |
|
70% =
70100 =
710 70% x 60 =
710 x 60 = 42
60 - 42 = 18
20% =
20100 =
15 The number of lemons is 27 less than the number of chikoos in the end. So, if another 27 lemons are added, the number of lemons and chikoos in the end will be the same.
3 u + 18 + 27 = 8 u
3 u + 45 = 8 u
8 u - 3 u = 45
5 u = 45
1 u = 45 ÷ 5 = 9
Number of lemons left
= 3 u + 18
= 3 x 9 + 18
= 27 + 18
= 45
Total number of fruits left
= 3 u + 18 + 8 u
= 11 u + 18
= 11 x 9 + 18
= 99 + 18
= 117
Lemons leftTotal fruits left =
45117 =
513 Answer(s):
513 
