Level 3
The figure shows a circle with centre O and diameter, 14 cm. ABCD and OAEB are squares. Find the total area of the shaded portions of the figure. (Take π = 227)
4 m
Level 3
The figure is made up of semicircles, a square, ABDF, and a rectangle, BCEF. The length of the square, ABDF, is 20 cm. Find the area of the shaded figure. Leave the answer in terms of π .
4 m
Level 3
The figure is made up of a quadrant, a square and a semicircle. The area of the square is 144 cm2. Find the area of the shaded parts. (Take π = 3.14)
4 m
Level 3
Find (a) the area and (b) the perimeter of the figure. (Take π = 227)
4 m
Level 3
Find the:
  1. area and
  2. perimeter of the shaded part. The diameter of the small circle is 6 cm. (Take π = 3.14)
4 m
Level 3
The figure is made up of identical quadrants. The radius is 10 cm long. Take π as 3.14.
  1. Find the area of the shaded part.
  2. Find the perimeter of the shaded part.
4 m
Level 3 PSLE
OPQRS is part of a circle of radius 10 cm. OPR and OQS are quarter circles. The area of the shaded part OQR is 40 cm2 and the perimeter of the shaded part OQR is 30 cm. For each of the following, use the calculator value of π to find:
  1. the area of the figure OPQRS, correct to 2 decimal places,
  2. the perimeter of the figure OPQRS, correct to 1 decimal places.
4 m
Level 3
The figure shows one big quadrant and two small semicircles. The radius of the big quadrant is 60 cm.
  1. Find the perimeter of the shaded figure. (Take π = 3.14)
  2. Find the shaded area of this figure. (Take π = 3.14)
4 m
Level 3
In the figure, WXYZ and XYML are squares. P and N are centres of square WXYZ and PQRS respectively. O is the centre of XY. If WL = 56 cm, take π = 227 and find
  1. the perimeter of the shaded region,
  2. the area of the shaded region.
4 m
Level 3
The figure is not drawn to scale. It is formed by quadrants and semicircles of two sizes. The radius of the larger quadrant is 3 cm longer than the radius of the smaller quadrant. The radius of the smaller quadrant (Line B) is 12 cm.
  1. Find the area of the shaded part.
  2. Find the perimeter of the dotted line. (Take π = 3.14)
4 m