Question:

Level 3 PSLE

The figure shows a rectangle with its corners cut out. Each of the 4 identical corners cut out is a quarter circle. The ratio of the length of the rectangle to its breadth is 13 : 5.

The figure shows a rectangle with its corners cut out. Each of the 4 identical corners cut out is a quarter circle. The ratio of the length of the rectangle to its breadth is 13 : 5.

- What is the radius of each quarter circle?
- What is the perimeter of the shaded part. Take &pi = 3.14. Give your answer correct to 1 decimal place.

5 m

Level 3

The figure shows 2 identical circles enclosed in a rectangle ABCD. Find the area of the shaded parts. (Take π = 3.14)

The figure shows 2 identical circles enclosed in a rectangle ABCD. Find the area of the shaded parts. (Take π = 3.14)

5 m

Level 3

The figure is made up of a big quadrant OWY a small quadrant OVZ and a square VXZO. The radius of the big quadrant OWY is 12cm. The area of the big quadrant is twice the area of the small quadrant OVZ. Using the calculator value of π, find the area of the shaded parts, correct to 2 decimal places.

The figure is made up of a big quadrant OWY a small quadrant OVZ and a square VXZO. The radius of the big quadrant OWY is 12cm. The area of the big quadrant is twice the area of the small quadrant OVZ. Using the calculator value of π, find the area of the shaded parts, correct to 2 decimal places.

5 m

Level 3

The figure, not drawn to scale, is made up of a square, a quadrant and a semicircle. WXYZ is a square of side 28 cm. Find the area of the shaded part. (Take π =^{22}_{7})

The figure, not drawn to scale, is made up of a square, a quadrant and a semicircle. WXYZ is a square of side 28 cm. Find the area of the shaded part. (Take π =

5 m

Level 3 PSLE

The figure shows a table cloth. The outside edge of the mat is formed by 4 semicircles and 2 quarter circles, each of radius 14 cm.

The figure shows a table cloth. The outside edge of the mat is formed by 4 semicircles and 2 quarter circles, each of radius 14 cm.

- Find the perimeter of the mat.
**2 m** - Find the area of the mat. Take π =
^{22}_{7}.**3 m**

5 m