Level 3 PSLE
Tom designed a logo as shown. The logo is made up of 2 small identical quarter circles, a large quarter circle and 2 straight lines drawn inside a square of side 42 cm. The radius of each small quarter circle is 14 cm.
  1. What is the perimeter of the shaded part?
  2. What is the area of the shaded part?
4 m
Level 3
The figure shows a rectangle with its corners cut out. Each of the 4 identical corners cut out is a quarter circle. The ratio of the length of the rectangle to its breadth is 13 : 5.
  1. What is the radius of each quarter circle?
  2. What is the perimeter of the shaded part. Take π = 3.14. Give your answer correct to 1 decimal place.
5 m
Level 3
The figure shows 2 identical circles enclosed in a rectangle ABCD. Find the area of the shaded parts. (Take π = 3.14)
5 m
Level 3
The figure is made up of a big quadrant OWY a small quadrant OVZ and a square VXZO. The radius of the big quadrant OWY is 12cm. The area of the big quadrant is twice the area of the small quadrant OVZ. Using the calculator value of π, find the area of the shaded parts, correct to 2 decimal places.
5 m
Level 3
The figure, not drawn to scale, is made up of a square, a quadrant and a semicircle. WXYZ is a square of side 28 cm. Find the area of the shaded part. (Take π = 227)
5 m
Level 3 PSLE
The figure shows a table cloth. The outside edge of the mat is formed by 4 semicircles and 2 quarter circles, each of radius 14 cm.
  1. Find the perimeter of the mat.
  2. Find the area of the mat. Take π = 227.
5 m
Level 3 PSLE
The figure is made up of a rectangle, semicircles and quarter circles. The area of the rectangle is 216 cm2.
  1. Find the perimeter of the rectangle.
  2. Find the area of the figure. Take π = 3.14
5 m
Level 3 PSLE
A small circle with centre O has been cut from a circular piece of cardboard with the same centre. The radius of the small circle is 8 cm.
The remaining cardboard is then cut into four equal parts along the dotted lines as shown in Figure 1. The four parts are rearranged to form a new shape in Figure 2.
  1. Find the area of the new shape.
  2. Find the perimeter of the new shape. (Take π = 3.14)
5 m