Level 1
Find the perimeter of this quadrant. Its radius is 4 cm. (Take π = 3.14)
1 m
Level 3
The figure is made up of a circle, a triangle and a square of sides 8 cm. The radius of the circle is 7 cm. The ratio of the area of the circle to the shaded area of the circle is 7 : 3. The ratio of the area of the square to the area of the triangle is 1 : 4. Given that 14 of the square is shaded, what is the total area of the unshaded figure? (Take π = 227)
4 m
Level 2
In the figure, the circle is touching each of the two squares at exactly four points, if the area of the bigger square is 100 cm2, find the area of the smaller square.
2 m
Level 2
The circles are not drawn to scale. The small circle is with radius a and the big circle is with radius A. The ratio of a to A is 4 : 7. If the area of the small circle is 169π cm2, find A. Express the answer in mixed number.
2 m
Level 2
The perimeter of the triangle WXY is 30 cm. Given that YW = 13 cm, WX = 12 cm, RY = PY and PX = QX, find the radius of the circle.
2 m
Level 2
The figure shows a circle. O is the centre and the diameter XOY is 42 cm long. Each of the shaded part is formed by the radius of the big circle and 2 identical quarter arcs. Find the total area of the shaded parts in the figure. (Take π = 227)
2 m
Level 2
The figure shows 2 identical small circles of diameter 12 cm inside a big circle of radius 12 cm. Find the area of the unshaded part of the big circle. Express the answer in terms of π.
2 m
Level 2
The figure (not drawn to scale) is made of two concentric circles. AB is the radius of the bigger circle. AC is the radius of the smaller circle. AB is 35 cm while AC is 14 cm. Find the area of the shaded region. (Take π = 227)
2 m
Level 2
The shaded figure is made up of 4 quarter arcs of radius 12 cm. Find its area. (Take π = 3.14)
2 m
Level 2
The figure is formed by a circle and an isosceles triangle where PQ = PR. The radius of the circle is 14 cm. Find the area of the shaded part. (Take π = 227)
2 m