Jar V contains 50-cent coins and Jar W contains 5-cent coins. There are 12 more coins in Jar W than in Jar V. The amount of money in Jar V is 840¢ more than the amount of money in Jar W. How many total coins are there?
| |
Jar V |
Jar W |
| Number |
1 u |
1 u + 12 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 60 |
Total value of 50¢ coins in Jar V
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Jar W
= 5 x (1 u + 12)
= 5 u + 60
The amount in Jar V is 840¢ more than Jar W. If another 840¢ is added into Jar W, both Jar V and Jar W will have the same amounts of money.
50 u = 5 u + 60 + 840
50 u - 5 u = 60 + 840
45 u = 900
1 u = 900 ÷ 45 = 20
Total number of coins
= 1 u + (1 u + 12)
= 2 u + 12
= 2 x 20 + 12
= 40 + 12
= 52
Answer(s): 52
