Coin Box Z contains 50-cent coins and Coin Box A contains 5-cent coins. There are 39 more coins in Coin Box A than in Coin Box Z. The amount of money in Coin Box Z is 930¢ more than the amount of money in Coin Box A. How many total coins are there?
| |
Coin Box Z |
Coin Box A |
| Number |
1 u |
1 u + 39 |
| Value |
50¢ |
5¢ |
| Total value |
50 u |
5 u + 195 |
Total value of 50¢ coins in Coin Box Z
= 50 x 1 u
= 50 u
Total value of 5¢ coins in Coin Box A
= 5 x (1 u + 39)
= 5 u + 195
The amount in Coin Box Z is 930¢ more than Coin Box A. If another 930¢ is added into Coin Box A, both Coin Box Z and Coin Box A will have the same amounts of money.
50 u = 5 u + 195 + 930
50 u - 5 u = 195 + 930
45 u = 1125
1 u = 1125 ÷ 45 = 25
Total number of coins
= 1 u + (1 u + 39)
= 2 u + 39
= 2 x 25 + 39
= 50 + 39
= 89
Answer(s): 89
