Hazel had a total of 421 red and brown beads. She used
45 of her red beads and bought another 47 brown beads. The number of brown beads she had then become
15 the number of red beads. How many less brown beads than red beads did she have at first?
|
Red beads |
Brown beads |
Before |
5x5 |
|
Change |
- 4x5 |
+ 47 |
After |
1x5 |
|
Comparing beads in the end |
5x1 |
1x1 |
|
Red beads |
Brown beads |
Before |
25 u |
1 u - 47 |
Change |
- 20 u |
+ 47 |
After |
5 u |
1 u |
The number of red beads in the end is repeated.
LCM of 1 and 5 is 5.
Total number of red beads and brown beads
= 25 u + 1 u - 47
= 26 u - 47
26 u - 47 = 421
26 u = 421 + 47
26 u = 468
1 u = 468 ÷ 26 = 18
Number of less brown beads than red beads at first
= 25 u - (1 u - 47)
= 24 u + 47
= 24 x 18 + 47
= 479
Answer(s): 479