Marion, Victoria and Sarah were playing with beads. Marion started with 32 beads and in the first game, she won ¹₂ more beads from Victoria. In the second game, Marion lost ⁵₈ of her original number of beads to Sarah. Victoria lost as many beads as Marion to Sarah. In the final game, Marion won ¹₄ of her original number of beads from Victoria. All of them ended up with the same number of beads.

1. How many beads did Marion have in the end?
2. How many beads did Victoria have at first?

	Marion	Victoria	Sarah
Before	32
First game	+ 16	- 16
Second game	- 20		+ 20
		- 20	+ 20
Final game	+ 8	- 8
After	1 u	1 u	1 u

(a)
Number of beads that Marion won from Victoria
= ¹₂ x 32
= 16

Number of beads that Marion lost to Sarah
= ⁵₈ x 32
= 20

Number of beads that Marion won from Victoria
= ¹₄ x 32
= 8

Number of beads that Marion had in the end
= 32 + 16 - 20 + 8
= 36

(b)
Number of beads that Victoria had at first
= 1 u + 8 + 20 + 16
= 36 + 8 + 20 + 16
= 80 

Answer(s): (a) 36 ; (b) 80