Tammy and Kimberly have some wafers each. If Tammy gives Kimberly 32 wafers, Tammy will have ²₅ as many wafers as Kimberly. If Tammy gives Kimberly 5 wafers, they will have an equal number of wafers. How many wafers does Kimberly have at first?

	Case 1		Case 2
	Tammy	Kimberly	Tammy	Kimberly
Before	2 u + 32	5 u - 32	3.5 u + 5	3.5 u - 5
Change	- 32	+ 32	- 5	+ 5
After	2 u	5 u	3.5 u	3.5 u

Total number of wafers that Tammy and Kimberly have
= 2 u + 5 u
= 7 u 

Number of wafers that Tammy and Kimberly each has in the end is the same.

Number of wafers that Tammy and Kimberly each has in the end in Case 2
= 7 u ÷ 2
= 3.5 u

Number of wafers that Tammy had at first is the same in Case 1 and Case 2.

3.5 u + 5 = 2 u + 32
3.5 u - 2 u = 32 - 5
0.5 u = 27

1 u = 27 ÷ 0.5 = 54

Number of wafers that Kimberly has
= 5 u - 32
= 5 x 54 - 32
= 270 - 32
= 238

Answer(s): 238