A stallholder had the same number of persimmons, pomegranates and kiwis at first. After 82 kiwis, some persimmons and pomegranates were thrown away, there were 97 fruits left. There were twice as many persimmons as pomegranates left. The number of kiwis left was 33 fewer than the number of persimmons. How many pomegranates were thrown away?
| |
Persimmons |
Pomegranates |
Kiwis |
Total |
| Before |
1 |
1 |
1 |
|
| Change |
- ? |
- ? |
- 82 |
|
| After |
2 u |
1 u |
2 u - 33 |
97 |
Total number of fruits in the end
= 2 u + 1 u + 2 u - 33
= 5 u - 33
5 u - 33 = 97
5 u = 97 + 33
5 u = 130
1 u = 130 ÷ 5 = 26
Number of kiwis at first
= 2 u - 33 + 82
= 2 x 26 - 33 + 82
= 52 - 33 + 82
= 101
The number of pomegranates and kiwis at first was the same.
Number of pomegranates thrown away
= 101 - 1 u
= 101 - 26
= 75
Answer(s): 75
