Dylan has $17. Will has $4
e more than Dylan. David has $2
e less than Will.
- Find the amount of money that David has in terms of e.
- Find the total amount of money that the three boys have in terms of e.
- If e = 6, how much does David have?
(a)
Amount that Dylan has = $17
Amount that Will has = $(17 + 4
e)
Amount that David has
= 17 + 4
e - 2
e = $(17 + 2
e)
(b)
Total amount that the three boys have
= 17 + 17 + 4
e + 17 + 2
e= 17 + 17 + 17 + 4
e + 2
e = $(51 + 6
e)
(c)
Amount that David has
= 17 + 2
e= 17 + 2 x 6
= 17 + 12
= $29
Answer(s): (a) $(17 + 2
e) or $(2
e + 17); (b) $(51 + 6
e) or $(6
e + 51); (c) $29