Ahmad has $16. Bobby has $5
n more than Ahmad. David has $2
n less than Bobby.
- Find the amount of money that David has in terms of n.
- Find the total amount of money that the three boys have in terms of n.
- If n = 5, how much does David have?
(a)
Amount that Ahmad has = $16
Amount that Bobby has = $(16 + 5
n)
Amount that David has
= 16 + 5
n - 2
n = $(16 + 3
n)
(b)
Total amount that the three boys have
= 16 + 16 + 5
n + 16 + 3
n= 16 + 16 + 16 + 5
n + 3
n = $(48 + 8
n)
(c)
Amount that David has
= 16 + 3
n= 16 + 3 x 5
= 16 + 15
= $31
Answer(s): (a) $(16 + 3
n) or $(3
n + 16); (b) $(48 + 8
n) or $(8
n + 48); (c) $31