Sean is
g years old. Flynn is six times as old as Sean and Xavier is 8 years younger than Flynn.
- Express Xavier's age in terms of g.
- Sean is 10 years old as of now. ln how many years' time will Xavier be 4 times as old as Sean?
(a)
Sean's age =
g years
Flynn's age = 6
g years
Xavier's age = (6
g - 8) years
(b)
g = 10
Difference in age remains unchanged.
Difference in age between Xavier and Sean
= (6
g - 8) -
g = 6
g -
g - 8
= 5
g - 8
= 5 x 10 - 8
= 42 years
Difference in the age when Xavier will be 4 times as old as Sean
= 4 u - 1 u
= 3 u
3 u = 42
1 u = 42 ÷ 3 = 14
Number of years' time so Xavier will be 4 times as old as Sean
= 14 - 10
= 4 years
Answer(s): (a) (6
g - 8) years; (b) 4 years
