The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube S and Cube T. The tank is filled with some water. Cube S is ⁴₅ filled with 100000 mℓ of water while Cube T is completely filled with water. The height of the water level in Cube S is 8 cm higher than that in Cube T. Water is then drained from the tank and the height of the new water level is 6 cm. What is the volume of the water drained in mℓ?
⁴₅ of the volume of Cube S = 100000 mℓ

Volume of Cube S
= 100000 ÷ ⁴₅
= 100000 x ⁵₄
= 125000 mℓ

Length of Cube S
= ³√125000
= 50 cm 

Height of water in Cube S at first
= ⁴₅ x 50
= 40 cm

Height of Cube T
= 40 - 8
= 32 cm

Height decrease in water in Cube S after draining
= 40 - 6
= 34 cm

Height decrease in water in Cube S after draining
= 32 - 6
= 26 cm

Volume of water drained in Cube S
= 50 x 50 x 34
= 85000 mℓ

Volume of water drained in Cube T
= 32 x 32 x 26
= 26624 mℓ

Total volume of water drained
= 85000 + 26624
= 111624 mℓ

Answer(s): 111624 mℓ