The diagram shows 3 tanks of different dimensions, each separated by a partition. Tank V, measuring 60 m by 34 m by 29 m, is filled with water to its brim. Tank U is an empty cuboidal container with a length of 27 m. Slider 1 is lifted to release ²₅ of the water from Tank V to Tank U, after which the partition is slid down to separate Tank V and Tank U. Next, Slider 2 is removed and some water from Tank U flows into Tank T such that the height of the water level of Tank U and Tank T is 6 m.

1. What is the length of Container T?
2. How many m³ of water are there in Container U?

(a)
Volume of water in the Tank V that flows into the Container U
= 60 x 34 x 29 x ²₅ 
= 23664 m³ 

Base area of Tank U and Tank T
= 23664 ÷ 6
= 3944 m² 

Length of Tank T and Tank U
= 3944 ÷ 34
= 116 m

Length of Tank T
= 116 - 27
= 89 m

(b)
Volume of water in Tank U
= 27 x 34 x 6
= 5508 m³ 

Answer(s): (a) 89 m; (b) 5508 m³