H and J are two rectangular containers. The base area of H is 78 cm
2 while that of J is 46 cm
2 . At first, H contained water to a height of 42 cm and J was empty, as shown.
- What was the volume of the water in H at first?
- Neave then poured some water from H to J. After that, the height of the water level in H was thrice that in J. What was the new height of the water level in H?
(a)
Volume of water in H
= 78 x 42
= 3276 cm
3 (b)
Total base areas
= 78 x 3 + 46
= 280 cm
2 Height of water if the total base area is 280 cm
2 = 3276 ÷ 280
= 11.7 cm
New height of the water level in H
= 11.7 x 3
= 35.1 cm
Answer(s): (a) 3276 cm
3; (b) 35.1 cm