The figure is not drawn to scale. AB//DC and CB//EA. Triangles AEB and BCD are isosceles triangles. Find
- ∠n
- ∠p.
(a)
∠BCD = ∠BAE = 74° (CB//EA, BA//CD)
∠ABE
= (180° - 74°) ÷ 2
= 106° ÷ 2
= 53° (Isosceles triangle)
∠CBD
= 180° - 74° - 74°
= 32° (Isosceles triangle)
∠n
= 180° - 74° - 53° - 32°
= 21° (Interior angles, BA//CD)
(b)
∠p
= 180° - 26° - 21°
= 133° (Angles sum of triangle)
Answer(s): (a) 21°; (b) 133°
