The figure is not drawn to scale. HJ//LK and KJ//MH. Triangles HMJ and JKL are isosceles triangles. Find
- ∠d
- ∠e.
(a)
∠JKL = ∠JHM = 78° (KJ//MH, JH//KL)
∠HJM
= (180° - 78°) ÷ 2
= 102° ÷ 2
= 51° (Isosceles triangle)
∠KJL
= 180° - 78° - 78°
= 24° (Isosceles triangle)
∠d
= 180° - 78° - 51° - 24°
= 27° (Interior angles, JH//KL)
(b)
∠e
= 180° - 26° - 27°
= 127° (Angles sum of triangle)
Answer(s): (a) 27°; (b) 127°
