The figure, not drawn to scale, O is the centre of the circle and RW // SV // TU. Find
- ∠QOT
- ∠QVO
(a)
∠WOS
= 180° - 98°
= 82° (Interior angles, RW//SO)
∠OTV = ∠OVT = 30° (Isosceles triangle)
∠SOT
= 30° + 30°
= 60° (Exterior angle of a triangle)
∠QOT
= 82° + 60°
= 142°
(b)
∠VOT
= 180° - 30° -30°
= 120° (Isosceles triangle)
∠QOV
= 360° - 142° - 120°
= 98° (Angles at a point)
QO = OV = Radius
∠QVO
= (180° - 98°) ÷ 2
= 82° ÷ 2
= 41° (Isosceles triangle)
Answer(s): (a) 142°; (b) 41°
