The figure, not drawn to scale, O is the centre of the circle and GM // HL // JK. Find
- ∠FOJ
- ∠FLO
(a)
∠MOH
= 180° - 96°
= 84° (Interior angles, GM//HO)
∠OJL = ∠OLJ = 29° (Isosceles triangle)
∠HOJ
= 29° + 29°
= 58° (Exterior angle of a triangle)
∠FOJ
= 84° + 58°
= 142°
(b)
∠LOJ
= 180° - 29° -29°
= 122° (Isosceles triangle)
∠FOL
= 360° - 142° - 122°
= 96° (Angles at a point)
FO = OL = Radius
∠FLO
= (180° - 96°) ÷ 2
= 84° ÷ 2
= 42° (Isosceles triangle)
Answer(s): (a) 142°; (b) 42°