A box of croissants is shared among three children. Cody gets 6 times as many croissants as Bobby. Bobby gets twice as many croissants as Seth. What fraction of the box of croissants does Cody get?
| Cody |
Bobby |
Seth |
Total |
| 6x2 |
1x2 |
|
|
| |
2x1 |
1x1 |
|
| 12 u |
2 u |
1 u |
15 u |
The number of Bobby's croissants is the repeated identity. Make the number of Bobby's croissants the same. LCM of 1 and 2 is 2.
Total pieces of croissants
= 12 u + 2 u + 1 u
= 15 u
Fraction of the box of croissants that Cody gets
=
1215 =
45 Answer(s):
45 
