The figure, not drawn to scale, is made up of Rectangle D and Rectangle E overlapping each other. The area of Rectangle D is
18 the area of Rectangle E. Given that
12 of Rectangle D is shaded. What fraction of the total area of the figure is unshaded?
Rectangle D |
Rectangle E |
1x2 = 2 u |
8x2 = 16 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
1x1 |
1x1 |
|
1 u |
1 u |
1 u |
15 u |
Rectangle D and Rectangle E share the same shaded area.
Rectangle D is the combined repeated identity. Make the area of Rectangle D the same. LCM of 1 and 2 is 2.
Total unshaded areas
= 1 u + 15 u
= 16 u
Total area of the figure
= 1 u + 1 u + 15 u
= 17 u
Fraction of the figure unshaded
=
1617 Answer(s):
1617