Tammy, Julie and Roshel each had some marbles and decided to play a game with their marbles. In round 1, Tammy lost
13 of her marbles to Julie. In round 2, Julie lost
13 of her total number of marbles to Roshel. In round 3, Roshel lost
13 of her total number of marbles to Tammy. In the end, Tammy, Julie and Roshel had 123, 86 and 50 marbles respectively. How many marbles did Julie have at first?
|
Tammy |
Julie |
Roshel |
|
|
80 |
|
Before 1 |
3 b |
|
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
2 b |
129 |
|
Before 2 |
98 |
3 u |
|
Change 2 |
|
- 1 u |
+ 1 u |
After 2 |
|
2 u |
75 |
Before 3 |
|
|
3 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
2 p |
Comparing Tammy, Julie and Roshel in the end |
123 |
86 |
50 |
Working backwards.
2 p = 50
1 p = 50 ÷ 2 = 25
At the start of Round 3:
Number of marbles that Roshel had
= 3 p
= 3 x 25
= 75
2 u = 86
1 u = 86 ÷ 2 = 43
At the start of Round 2:
Number of marbles that Julie had
= 3 u
= 3 x 43
= 129
At the start of Round 2:
Number of marbles that Tammy had
= 123 - 25
= 98
2 b = 98
1 b = 98 ÷ 2 = 49
At the start of Round 1:
Number of marbles that Julie had
= 129 - 1 b
= 129 - 49
= 80
Answer(s): 80