Raeann, Zoe and Joelle each had some balls and decided to play a game with their balls. In round 1, Raeann lost
13 of her balls to Zoe. In round 2, Zoe lost
13 of her total number of balls to Joelle. In round 3, Joelle lost
13 of her total number of balls to Raeann. In the end, Raeann, Zoe and Joelle had 120, 100 and 72 balls respectively. How many balls did Zoe have at first?
|
Raeann |
Zoe |
Joelle |
|
|
108 |
|
Before 1 |
3 b |
|
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
2 b |
150 |
|
Before 2 |
84 |
3 u |
|
Change 2 |
|
- 1 u |
+ 1 u |
After 2 |
|
2 u |
108 |
Before 3 |
|
|
3 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
2 p |
Comparing Raeann, Zoe and Joelle in the end |
120 |
100 |
72 |
Working backwards.
2 p = 72
1 p = 72 ÷ 2 = 36
At the start of Round 3:
Number of balls that Joelle had
= 3 p
= 3 x 36
= 108
2 u = 100
1 u = 100 ÷ 2 = 50
At the start of Round 2:
Number of balls that Zoe had
= 3 u
= 3 x 50
= 150
At the start of Round 2:
Number of balls that Raeann had
= 120 - 36
= 84
2 b = 84
1 b = 84 ÷ 2 = 42
At the start of Round 1:
Number of balls that Zoe had
= 150 - 1 b
= 150 - 42
= 108
Answer(s): 108