There were some rows of stools in a parade square. Each row had 8 stools. When Mary brought in 2 extra stools and rearranged all the stools, there were 5 stools in each row and 4 more rows than before. How many stools were there at first?
|
First arrangement |
Second arrangement |
Number |
1 u |
1 u + 4 |
Value |
8 |
5 |
Total value |
8 u |
5 u + 20 |
If another 2 stools are added in the first arrangement, the total number of stools in the first arrangement and the second arrangement will be the same.
8 u + 2 = 5 u + 20
8 u - 5 u = 20 - 2
3 u = 18
1 u = 18 ÷ 3 = 6
Number of stools at first
= 8 u
= 8 x 6
= 48
Answer(s): 48