Dana made a profit of 60% from the sale of a blazer and a profit of 70% from the sale of a jacket. The total profit she made from the two items was $139. She later sold a similar blazer at a discount of 10% off the advertised price. Her total profit for the three items then increased to $158.80.

1. Find the profit made on the jacket.
2. How much did she sell the jacket for?

	Blazer 1	Jacket 1	Blazer 2
Cost Price	5 u	10 p	5 u
Profit	+ 3 u	+ 7 p	+ 3 u
Selling Price	8 u	17 p	8 u
Discount			- 0.8 u
Discounted Price			7.2 u

100% + 60% = 160%
160% = ¹⁶⁰₁₀₀ = ⁸₅

100% + 70% = 170%
170% = ¹⁷⁰₁₀₀ = ¹⁷₁₀

(a)
Selling price of the blazer
= 100% of the price of the blazer + 60% of the price of the blazer
= 5 u + 3 u
= 8 u

Selling price of the jacket
= 100% of the price of the jacket + 70% of the price of the jacket
= 10 p + 7 p
= 17 p

Price of the second blazer after 10% discount in percentage
= 100% - 10%
= 90%

Price of the second blazer after 10% discount in units
= 90% x 8 u
= ⁹⁰₁₀₀ x 8 u
= 7.2 u

Profit made for the second blazer in units
= 7.2 u - 5 u
= 2.2 u

2.2 u = 158.8 - 139 = 19.8

1 u = 19.8 ÷ 2.2 = 9

3 u + 7 p = 139
3 x 9 + 7 p = 139
27 + 7 p = 139

7 p
= 139 - 27
= $112

Profit made on the jacket = $112

(b)
1 p = 112 ÷ 7 = 16

Selling price of the jacket
= 17 p
= 17 x 16
= $272

Answer(s): (a) $112; (b) $272