The ratio of the number of chickens in Farm S to the number of chickens in Farm T was 3 : 7. There were 48 fewer chickens in Farm S than in Farm T. When 9 chickens escaped from Farm T, the farmer in Farm T bought another 15 chickens. What was the new ratio of the number of chickens in Farm S to the number of chickens in Farm T in the end? Give your answer in the simplest form.
|
Farm S |
Farm T |
Before |
3 u |
7 u |
Change 1 |
|
- 9 |
Change 2 |
|
+ 15 |
After |
3 u |
7 u + 6 |
Number of fewer chickens in Farm S than Farm T
= 7 u - 3 u
= 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Number of chickens in Farm S
= 3 u
= 12 x 3
= 36
Number of chickens in Farm T
= 7 u
= 12 x 7
= 84
New number of chickens in Farm T
= 7 u + 6
= 84 + 6
= 90
Farm S : Farm T
36 : 90
(÷ 18)2 : 5
Answer(s): 2 : 5