In the figure, PQS and UTlR are straight lines. ∠PUT = 46°, ∠UPT = 44°, ∠QRS = 34° and ∠QSR = 120°. Find
- ∠PTQ
- ∠TPQ
(a)
∠PTU
= 180° - 44° - 46°
= 90° (Angles sum of triangle)
∠PTQ
= 180° - 90°
= 90° (Angles on a straight line)
(b)
∠SQR
= 180° - 120° - 34°
= 26° (Angles sum of triangle)
∠PQT = ∠SQR = 26° (Vertically opposite angles)
∠TPQ
= 180° - 90° - 26°
= 64° (Angles sum of triangle)
Answer(s): (a) 90°; (b) 64°