In the figure, JKM and PNlL are straight lines. ∠JPN = 42°, ∠PJN = 40°, ∠KLM = 35° and ∠KML = 109°. Find
- ∠JNK
- ∠NJK
(a)
∠JNP
= 180° - 40° - 42°
= 98° (Angles sum of triangle)
∠JNK
= 180° - 98°
= 82° (Angles on a straight line)
(b)
∠MKL
= 180° - 109° - 35°
= 36° (Angles sum of triangle)
∠JKN = ∠MKL = 36° (Vertically opposite angles)
∠NJK
= 180° - 82° - 36°
= 62° (Angles sum of triangle)
Answer(s): (a) 82°; (b) 62°
