In the figure, BCD and DEF are isosceles triangles where BD = CD and DE = DF. Given that EG, FJ and BL are straight lines, find
- ∠HML
- ∠FGM
(a)
∠BCD = ∠CBD = ∠DEF = ∠DFE (Isosceles triangle)
∠DFE = ∠GFM = 43° (Verticallly opposite angles)
∠JFM
= 43° - 14°
= 29°
∠FHM
= 180° - 104°
= 76° (Angles on a straight line)
∠HML
= 76° + 29°
= 105° (Exterior angle of a triangle)
(b)
∠FGM
= 105° - 43°
= 62° (Exterior angle of a triangle)
Answer(s): (a) 105°; (b) 62°
