In the figure, EFG is parallel to HJK and HG cuts ∠FHJ equally. Given that ∠EFH = 58° and ∠FLG = 114°, find
- ∠t
- ∠v
(a)
∠EFH = ∠FHJ (Alternate angles)
∠t
= 58° ÷ 2
= 29°
(b)
∠FHL = ∠t = 29°
∠v
= 114° - 29°
= 85° (Exterior angle of a triangle)
Answer(s): (a) 29°; (b) 85°