CDEF is a rhombus. CFG is an equilateral triangle. Find
- ∠GCD
- ∠CDF
(a)
∠GCF
= 180° ÷ 3
= 60° (Equilateral triangle)
∠DCF = ∠DEF = 112° (Rhombus)
∠GCD
= 112° + 60°
= 172°
(b)
∠CDF
= (180° - 112°) ÷ 2
= 34° (Isosceles triangle)
Answer(s): (a) 172°; (b) 34°