In the diagram shown, BCD is a right-angled triangle and BC = CD = BE. Find
- ∠EBD
- ∠BEC
(a)
∠BDC
= (180° - 90°) ÷ 2
= 45° (Isosceles triangle)
∠EBD
= 45° - 31°
= 14°
(b)
∠BEC
= (180° - 31°) ÷ 2
= 74.5° (Isosceles triangle)
Answer(s): (a) 14°; (b) 74.5°