MQRU and MPSU are parallelograms and NTS is an isosceles triangle. Given that ∠NSP = 38°, ∠MUT = 64° and ∠QSR = 48°, find
- ∠PSQ,
- ∠QPS.
(a)
∠NST
= (180° - 21°) ÷ 2
= 79.5° (Isosceles triangle)
∠PSQ
= 180° - 79.5° - 38° - 48°
= 14.5° (Angles on a straight line)
(b)
∠QPS
= 180° - 48° -14.5°
= 117.5° (Interior angles)
Answer(s): (a) 14.5°; (b) 117.5°