In the figure, LEGK and LEFJ are parallelograms. Given that ∠GEH = 15°, ∠LKJ = 69° and LJK is an isosceles triangle where LJ = LK. Find
- ∠EHG
- ∠LEH
(a)
∠EGK
= 180° - 69°
= 111° (Interior angles)
∠EHG
= 180° - 111° - 15°
= 54° (Angles sum of triangle)
(b)
∠LEH
= ∠EHG
= 54° (Alternate angles)
Answer(s): (a) 54°; (b) 54°