In the figure, PHKN and PHJM are parallelograms. Given that ∠KHL = 12°, ∠PNM = 76° and PMN is an isosceles triangle where PM = PN. Find
- ∠HLK
- ∠PHL
(a)
∠HKN
= 180° - 76°
= 104° (Interior angles)
∠HLK
= 180° - 104° - 12°
= 64° (Angles sum of triangle)
(b)
∠PHL
= ∠HLK
= 64° (Alternate angles)
Answer(s): (a) 64°; (b) 64°