In the figure, JKLM is a trapezium and JMNR is a rhombus. JM is parallel to KL and MN = MP. RML and MQP are straight lines. ∠MJR = 44° and ∠QMR = 34°. Find
- ∠JML
- ∠MPN
(a)
∠JMR
= (180° - 44°) ÷ 2
= 68° (Isosceles triangle)
∠JML
= 180° - 68°
= 112° (Angles on a straight line)
(b)
∠PMN
= 68° - 34°
= 34°
∠MPN
= (180° - 34°) ÷ 2
= 73 ° (Isosceles triangle)
Answer(s): (a) 112°; (b) 73°