FGHJ is a rhombus, CDJ and GDH are straight lines. If GD = DJ, ∠DJH = 16° and ∠EGH = 29°, find
- ∠DHJ
- ∠ECD
(a)
∠DHJ
= 86° - 16°
= 70° (Exterior angle of a triangle)
(b)
∠GCD
= 86° - 29°
= 57° (Exterior angle of a triangle)
∠ECD
= 180° - 57°
= 123° (Angles on a straight line)
Answer(s): (a) 70°; (b) 123°