In the figure, LNQ and MNP are straight lines. NL = NM and PN = PQ. If ∠MLN = 51°, find
- ∠LNP
- ∠NPQ
(a)
∠LNP
= 51° + 51°
= 102° (Exterior angle of a triangle)
(b)
∠PNQ
= 180° - 102°
= 78° (Angles on a straight line)
∠NPQ
= 180° - 78° - 78°
= 24° (Isosceles triangle)
Answer(s): (a) 102°; (b) 24°