In the figure, EGJ and FGH are straight lines. GE = GF and HG = HJ. If ∠FEG = 60°, find
- ∠EGH
- ∠GHJ
(a)
∠EGH
= 60° + 60°
= 120° (Exterior angle of a triangle)
(b)
∠HGJ
= 180° - 120°
= 60° (Angles on a straight line)
∠GHJ
= 180° - 60° - 60°
= 60° (Isosceles triangle)
Answer(s): (a) 120°; (b) 60°