In the figure, EFG is parallel to KLM and the line KG cuts ∠FKM into half. Given that GK and FL are straight lines, ∠EFK = 50°, ∠KLJ = 37° and ∠FJG = 110°, find
- ∠d
- ∠f
- ∠e
(a)
∠KJL = ∠FJG = 110° (Vertically opposite angles)
∠d
= 180° - 110° - 37°
= 33° (Angles sum of triangle)
(b)
∠f
= 180° - 33°
= 147° (Interior angles)
(c)
∠e
= 180° - 33° - 33° - 37°
= 93° (Angles sum of triangle)
Answer(s): (a) 33°; (b) 147°; (c) 93°