A list of 17 numbers has an average of 340. When two numbers are deleted from the list, the average of the remaining numbers is 313.
- What is the sum of 17 numbers?
- What is the bigger number between the two numbers that have been deleted given that the difference between the two numbers is 3?
(a)
Sum of the 17 numbers
= 17 x 340
= 5780
(b)
Remaining numbers
= 17 - 2
= 15
Sum of the remaining numbers
= 313 x 15
= 4695
Sum of the two numbers
= 5780 - 4695
= 1085
Smaller number = 1 u
Bigger number = 1 u + 3
Total = 1 u + 1 u + 3 = 2 u + 3
2 u + 3 = 1085
2 u = 1085 - 3
2 u = 1082
1 u = 1082 ÷ 2 = 541
Bigger number
= 1 u + 3
= 541 + 3
= 544
Answer(s): (a) 5780; (b) 544