Shiyun had
45 as many mochi balls as Neave. Neave had
35 as many mochi balls as Julian. If Julian had 104 more mochi balls than Shiyun, find the total number of mochi balls that was shared among these 3 children at first.
Shiyun |
Neave |
Julian |
4x3 |
5x3 |
|
|
3x5 |
5x5 |
12 u |
15 u |
25 u |
Neave is the repeated identity.
LCM of 5 and 3 = 15
Number of more mochi balls that Julian had more than Shiyun
= 25 u - 12 u
= 13 u
13 u = 104
1 u = 104 ÷ 13 = 8
Total number of mochi balls
= 12 u + 15 u + 25 u
= 52 u
= 52 x 8
= 416
Answer(s): 416